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18.03.2013

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(x + 10)(x - 2) > 0.

: x ∈ (-∞; -10) ∪ (2; +∞).


(x + 2)2(x - 1) > 0.

: x > 1.


x + 4

2x - 3

< 0.

: x ∈ (-4; 3/2).


(x + 1)(x + 2)(x + 3)(x + 4) ≤ 0.

: x ∈ [-4 ;-3] ∪ [-2; -1].


x

x2 - 4

≥ 0.

: x ∈ (-2; 0] ∪ (2; +∞).


x3 - 6x2 + 11x - 6 < 0.

: x ∈ (-∞; 1) ∪ (2; 3).


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