, .

" ", "" " ". .
18.03.2013

LiveJournal Vkontakte Facebook Twitter

1...2

(x + 7)3(3x - 2)

(x - 2)(x - 4)

≤ 0.

: x ∈ [-7; 2/3] ∪ (2; 4).


(x + 5)2

x - 10

< 0.

: x ∈ (-∞; -5) ∪ (-5; 10).


(x + 3)5(x - 4)2 ≤ 0.

: x ∈ (-∞; -3] ∪ {4}.


(x - 1)(x - 2)(x + 3)2 < 0.

: x ∈ (1; 2).


1...2
2009-2012 . " - !" - , . .
Rambler's Top100