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18.03.2013

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cos2x = 1/2.

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:

2x = ±arccos(1/2) + 2πn = ±π/3 + 2πn ( , n ∈ Z).

x = ±π/6 + πn.

: x = ±π/6 + πn.


sin(3 - 2x) = -1/2.

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, :

3 - 2x = (-1)n(arcsin(-1/2)) + πn = (-1)n(-π/6) + πn ( nZ).

x = 3/2 + π/12(-1)n - πn/2.

: x = 3/2 + π/12(-1)n - πn/2.


sin3x = π/3.

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, π/3 > 1, .

: .


sinπ(x - 3) = 0 (-2; 6).

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, :

π(x - 3) = πn ( nZ).

x = n + 3.

xZ , , x ∈ (-2; 6), x ∈ {-1; 0; 1; 2; 3; 4; 5}.

: x ∈ {-1; 0; 1; 2; 3; 4; 5}.


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